Learn. Practise. Succeed.

Grade 7 Algebra: Expressions & Simple Equations

A letter can stand for a number whose value is not yet known. In the expression 3x + 2, the term 3x means three multiplied by x. An expression does not contain an equals sign. An equation, such as 3x + 2 = 14, states that two expressions have the same value. Solving means finding the value that makes that statement true.

Find material for your learning needs

Choose your grade, subject and topic. Explore existing resources or preview a custom request, with the exact price before purchase.

Find learning material

Original independent learning guide. Not official KICD content.

Collect like terms

Terms can be combined when their variable parts match. In 2x + 5x, both terms count the same kind of quantity, so their sum is 7x. In 2x + 5, the 5 is a constant and cannot be combined with 2x to make 7x. You can think of two identical bags plus five loose counters: the bags and counters are different units.

Worked example: solve 3x + 2 = 14

Subtract 2 from both sides to obtain 3x = 12. Then divide both sides by 3 to obtain x = 4. Each operation keeps the sides balanced. Check in the original equation: 3 × 4 + 2 = 14. This final check can catch an arithmetic error even when the chosen method was correct.

From words to an equation

Suppose three identical notebooks and a KSh 20 pen cost KSh 140 in a made-up practice problem. If x is the price of one notebook, write 3x + 20 = 140. Subtract 20 and divide by 3: x = 40. The answer is KSh 40 per notebook. Define the letter before writing the equation so that the units remain clear.

Avoid a common shortcut error

Changing a sign without knowing why can hide a mistake. Instead of saying a number simply moves across the equals sign, name the operation performed on both sides. Keep your working on separate lines. If your answer does not satisfy the original equation, locate the first line that is no longer equivalent.

Practice questions

  1. Simplify 4a + 3a − 2.

  2. Solve 2x + 7 = 19.

  3. Five equal packets contain 35 counters altogether. Write and solve an equation for counters per packet.

Answers and explanations
  1. The like terms give 7a − 2. The constant −2 remains separate.

  2. Subtract 7: 2x = 12. Divide by 2: x = 6. Check: 2 × 6 + 7 = 19.

  3. Let c be counters per packet. Then 5c = 35, so c = 7. Each packet contains seven counters.

Revision and exam practice

Free topic lessons

Work through the explanation and examples, then try the questions before checking the answers.

Available revision resources

Examinations and marking guidance

No full examination paper or standalone marking scheme is available in this selection. Use the visible answer explanations to check your practice; they do not represent an official assessment.

More learning support

Find reusable learning resources for your next lesson, examination practice or revision session.

Continue learning